Current sensor transfer impedance determination method

Theory

The left impedance is the signal generator which is generating enough power for 1 ampere.

This 1Amp. generates $P=I^{2}*R=50\ Watt$ in the right impedance.

The current sensor has 1 ohm transfer impedance, this means 1 ampere generates 1 Volt on the measuring part below.

The power in the lower 50 ohm impedance is $P={\frac {U^{2}}{R}}=20\ mWatt$

Reference measurement

Probe measurement

Calculation

$Correction\ factor(dB)=P_{Measured}-P_{Reference}+33.98$

$P_{Measured}$ and $P_{Reference}$ in dBm.

Note: This method is not a replacement for a real calibration.